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6z^2=150z
We move all terms to the left:
6z^2-(150z)=0
a = 6; b = -150; c = 0;
Δ = b2-4ac
Δ = -1502-4·6·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-150}{2*6}=\frac{0}{12} =0 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+150}{2*6}=\frac{300}{12} =25 $
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